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Ashbaugh Hill, New York Ashbaugh Hill is a summit located in Steuben County, NY at N42.28313° W77.64332° (NAD83) and at an elevation of 1653 ft MSL. It can be seen on the USGS 1:24K topographic map Hornell, NY.
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Note: Coordinates in the location and feature list above are referenced to NAD83 datum. |